Optimal. Leaf size=99 \[ \frac {3 a^3 \sec ^5(c+d x)}{35 d}+\frac {2 a \sec ^7(c+d x) (a+a \sin (c+d x))^2}{7 d}+\frac {3 a^3 \tan (c+d x)}{7 d}+\frac {2 a^3 \tan ^3(c+d x)}{7 d}+\frac {3 a^3 \tan ^5(c+d x)}{35 d} \]
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Rubi [A]
time = 0.06, antiderivative size = 99, normalized size of antiderivative = 1.00, number of steps
used = 4, number of rules used = 3, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.143, Rules used = {2755, 2748,
3852} \begin {gather*} \frac {3 a^3 \tan ^5(c+d x)}{35 d}+\frac {2 a^3 \tan ^3(c+d x)}{7 d}+\frac {3 a^3 \tan (c+d x)}{7 d}+\frac {3 a^3 \sec ^5(c+d x)}{35 d}+\frac {2 a \sec ^7(c+d x) (a \sin (c+d x)+a)^2}{7 d} \end {gather*}
Antiderivative was successfully verified.
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Rule 2748
Rule 2755
Rule 3852
Rubi steps
\begin {align*} \int \sec ^8(c+d x) (a+a \sin (c+d x))^3 \, dx &=\frac {2 a \sec ^7(c+d x) (a+a \sin (c+d x))^2}{7 d}+\frac {1}{7} \left (3 a^2\right ) \int \sec ^6(c+d x) (a+a \sin (c+d x)) \, dx\\ &=\frac {3 a^3 \sec ^5(c+d x)}{35 d}+\frac {2 a \sec ^7(c+d x) (a+a \sin (c+d x))^2}{7 d}+\frac {1}{7} \left (3 a^3\right ) \int \sec ^6(c+d x) \, dx\\ &=\frac {3 a^3 \sec ^5(c+d x)}{35 d}+\frac {2 a \sec ^7(c+d x) (a+a \sin (c+d x))^2}{7 d}-\frac {\left (3 a^3\right ) \text {Subst}\left (\int \left (1+2 x^2+x^4\right ) \, dx,x,-\tan (c+d x)\right )}{7 d}\\ &=\frac {3 a^3 \sec ^5(c+d x)}{35 d}+\frac {2 a \sec ^7(c+d x) (a+a \sin (c+d x))^2}{7 d}+\frac {3 a^3 \tan (c+d x)}{7 d}+\frac {2 a^3 \tan ^3(c+d x)}{7 d}+\frac {3 a^3 \tan ^5(c+d x)}{35 d}\\ \end {align*}
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Mathematica [A]
time = 0.01, size = 134, normalized size = 1.35 \begin {gather*} \frac {13 a^3 \sec ^7(c+d x)}{35 d}+\frac {a^3 \sec ^6(c+d x) \tan (c+d x)}{d}+\frac {a^3 \sec ^5(c+d x) \tan ^2(c+d x)}{5 d}-\frac {a^3 \sec ^4(c+d x) \tan ^3(c+d x)}{d}+\frac {4 a^3 \sec ^2(c+d x) \tan ^5(c+d x)}{5 d}-\frac {8 a^3 \tan ^7(c+d x)}{35 d} \end {gather*}
Antiderivative was successfully verified.
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Maple [B] Leaf count of result is larger than twice the leaf count of optimal. \(216\) vs.
\(2(89)=178\).
time = 0.19, size = 217, normalized size = 2.19
method | result | size |
risch | \(-\frac {16 \left (-6 a^{3} {\mathrm e}^{i \left (d x +c \right )}+i a^{3}+14 a^{3} {\mathrm e}^{3 i \left (d x +c \right )}-14 i a^{3} {\mathrm e}^{2 i \left (d x +c \right )}\right )}{35 \left ({\mathrm e}^{i \left (d x +c \right )}-i\right )^{7} \left ({\mathrm e}^{i \left (d x +c \right )}+i\right ) d}\) | \(84\) |
derivativedivides | \(\frac {a^{3} \left (\frac {\sin ^{4}\left (d x +c \right )}{7 \cos \left (d x +c \right )^{7}}+\frac {3 \left (\sin ^{4}\left (d x +c \right )\right )}{35 \cos \left (d x +c \right )^{5}}+\frac {\sin ^{4}\left (d x +c \right )}{35 \cos \left (d x +c \right )^{3}}-\frac {\sin ^{4}\left (d x +c \right )}{35 \cos \left (d x +c \right )}-\frac {\left (2+\sin ^{2}\left (d x +c \right )\right ) \cos \left (d x +c \right )}{35}\right )+3 a^{3} \left (\frac {\sin ^{3}\left (d x +c \right )}{7 \cos \left (d x +c \right )^{7}}+\frac {4 \left (\sin ^{3}\left (d x +c \right )\right )}{35 \cos \left (d x +c \right )^{5}}+\frac {8 \left (\sin ^{3}\left (d x +c \right )\right )}{105 \cos \left (d x +c \right )^{3}}\right )+\frac {3 a^{3}}{7 \cos \left (d x +c \right )^{7}}-a^{3} \left (-\frac {16}{35}-\frac {\left (\sec ^{6}\left (d x +c \right )\right )}{7}-\frac {6 \left (\sec ^{4}\left (d x +c \right )\right )}{35}-\frac {8 \left (\sec ^{2}\left (d x +c \right )\right )}{35}\right ) \tan \left (d x +c \right )}{d}\) | \(217\) |
default | \(\frac {a^{3} \left (\frac {\sin ^{4}\left (d x +c \right )}{7 \cos \left (d x +c \right )^{7}}+\frac {3 \left (\sin ^{4}\left (d x +c \right )\right )}{35 \cos \left (d x +c \right )^{5}}+\frac {\sin ^{4}\left (d x +c \right )}{35 \cos \left (d x +c \right )^{3}}-\frac {\sin ^{4}\left (d x +c \right )}{35 \cos \left (d x +c \right )}-\frac {\left (2+\sin ^{2}\left (d x +c \right )\right ) \cos \left (d x +c \right )}{35}\right )+3 a^{3} \left (\frac {\sin ^{3}\left (d x +c \right )}{7 \cos \left (d x +c \right )^{7}}+\frac {4 \left (\sin ^{3}\left (d x +c \right )\right )}{35 \cos \left (d x +c \right )^{5}}+\frac {8 \left (\sin ^{3}\left (d x +c \right )\right )}{105 \cos \left (d x +c \right )^{3}}\right )+\frac {3 a^{3}}{7 \cos \left (d x +c \right )^{7}}-a^{3} \left (-\frac {16}{35}-\frac {\left (\sec ^{6}\left (d x +c \right )\right )}{7}-\frac {6 \left (\sec ^{4}\left (d x +c \right )\right )}{35}-\frac {8 \left (\sec ^{2}\left (d x +c \right )\right )}{35}\right ) \tan \left (d x +c \right )}{d}\) | \(217\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.31, size = 122, normalized size = 1.23 \begin {gather*} \frac {{\left (15 \, \tan \left (d x + c\right )^{7} + 42 \, \tan \left (d x + c\right )^{5} + 35 \, \tan \left (d x + c\right )^{3}\right )} a^{3} + {\left (5 \, \tan \left (d x + c\right )^{7} + 21 \, \tan \left (d x + c\right )^{5} + 35 \, \tan \left (d x + c\right )^{3} + 35 \, \tan \left (d x + c\right )\right )} a^{3} - \frac {{\left (7 \, \cos \left (d x + c\right )^{2} - 5\right )} a^{3}}{\cos \left (d x + c\right )^{7}} + \frac {15 \, a^{3}}{\cos \left (d x + c\right )^{7}}}{35 \, d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.38, size = 112, normalized size = 1.13 \begin {gather*} \frac {8 \, a^{3} \cos \left (d x + c\right )^{4} - 36 \, a^{3} \cos \left (d x + c\right )^{2} + 15 \, a^{3} + 4 \, {\left (6 \, a^{3} \cos \left (d x + c\right )^{2} - 5 \, a^{3}\right )} \sin \left (d x + c\right )}{35 \, {\left (3 \, d \cos \left (d x + c\right )^{3} - 4 \, d \cos \left (d x + c\right ) - {\left (d \cos \left (d x + c\right )^{3} - 4 \, d \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: SystemError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 4.50, size = 138, normalized size = 1.39 \begin {gather*} -\frac {\frac {35 \, a^{3}}{\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 1} + \frac {525 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{6} - 1960 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 4025 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} - 4480 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 3143 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 1176 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 243 \, a^{3}}{{\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 1\right )}^{7}}}{280 \, d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 4.86, size = 228, normalized size = 2.30 \begin {gather*} \frac {2\,a^3\,\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )\,\left (13\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^7-43\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6\,\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )+77\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5\,{\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2-7\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4\,{\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3-105\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3\,{\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4+175\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2\,{\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5-105\,\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )\,{\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6+35\,{\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^7\right )}{35\,d\,{\left (\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )-\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )\right )}^7\,\left (\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )+\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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